(2x-1)(4x^2+2x+1)=0

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Solution for (2x-1)(4x^2+2x+1)=0 equation:


Simplifying
(2x + -1)(4x2 + 2x + 1) = 0

Reorder the terms:
(-1 + 2x)(4x2 + 2x + 1) = 0

Reorder the terms:
(-1 + 2x)(1 + 2x + 4x2) = 0

Multiply (-1 + 2x) * (1 + 2x + 4x2)
(-1(1 + 2x + 4x2) + 2x * (1 + 2x + 4x2)) = 0
((1 * -1 + 2x * -1 + 4x2 * -1) + 2x * (1 + 2x + 4x2)) = 0
((-1 + -2x + -4x2) + 2x * (1 + 2x + 4x2)) = 0
(-1 + -2x + -4x2 + (1 * 2x + 2x * 2x + 4x2 * 2x)) = 0
(-1 + -2x + -4x2 + (2x + 4x2 + 8x3)) = 0

Reorder the terms:
(-1 + -2x + 2x + -4x2 + 4x2 + 8x3) = 0

Combine like terms: -2x + 2x = 0
(-1 + 0 + -4x2 + 4x2 + 8x3) = 0
(-1 + -4x2 + 4x2 + 8x3) = 0

Combine like terms: -4x2 + 4x2 = 0
(-1 + 0 + 8x3) = 0
(-1 + 8x3) = 0

Solving
-1 + 8x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 8x3 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 8x3 = 0 + 1
8x3 = 0 + 1

Combine like terms: 0 + 1 = 1
8x3 = 1

Divide each side by '8'.
x3 = 0.125

Simplifying
x3 = 0.125

Reorder the terms:
-0.125 + x3 = 0.125 + -0.125

Combine like terms: 0.125 + -0.125 = 0.000
-0.125 + x3 = 0.000

The solution to this equation could not be determined.

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